Respuesta :

Answer:

[tex]{ \bf{consider \: points \: (5, \: 0) \: and \: (0, \: - 5)}} \\ { \tt{slope = \frac{ - 5 - 0}{0 - 5} }} \\ { \tt{m = 1}} \\ \\ { \tt{y = mx + c}} \\ 0 = ( 1 \times 5) + c \\ c = -5 \\ \\ { \bf{answer : { \tt{y = { \boxed{ 1}x + { \boxed{-5}}}}}}}[/tex]

sreedevi102

Answer:

[tex]y = [ 1 ] x + [ - 5 ][/tex]

Step-by-step explanation:

Let us consider 2 points through which the line passes.

[tex](x_1 , y _ 1 ) = ( 5 , 0 ) \ and \ (x _ 2 , y _ 2 ) = ( 0 , - 5 )[/tex]

Step 1 : Find slope, m

       [tex]slope, m = \frac{y _ 2 - y_ 1 }{x_ 2 - x_ 1 } = \frac{-5 - 0}{0-5} = \frac{-5}{-5} = 1[/tex]

Step 2 : Equation of line

         [tex](y - y_ 1) = m( x - x_1)\\\\( y - 0) = 1 ( x - 5)\\\\y = x - 5 \\\\y = x + ( -5)[/tex]

        [tex]y = (1) x + ( -5)[/tex]

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