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Answer:
[tex]{ \bf{from \: ionic \: product \: of \: water : }} \\ { \boxed{ \tt{k _{w} = [H _{3} O {}^{ + } ][OH {}^{ - } ]}}} \\ \\ { \tt{1 \times {10}^{ - 14} = (1 \times {10}^{ - 5} ) [OH {}^{ - } ]}} \\ \\ { \tt{[OH {}^{ - } ] = 1 \times {10}^{ - 9} }} \: M[/tex]
A solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.
What is [OH−] of the solution?
The water is made up of H2O only and when the pH of it is 7 then the concentration of all the ions would be the same while dissociation the water will get dissociate into H+ ions and OH- ions.
The concentration of OH- ions will be
OH- = Kw {H3O+}
{H3O+} = 1 × 10−5 M.
Kw = 14
substituting the value in the equation,
OH = 14 { 1 × 10−5 M.}
OH = 1 × 10−9 M
Therefore, the solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.
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