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PLEASE HELP!!

What is the reduction half-reaction for 2Mg + O2 —> 2MgO?

A) Mg -> Mg2+ + 2e-
B) O2 + 4e- -> 2O2-
C) Mg2+ + 2e- -> Mg
D) 2O2- -> O2 + 4e-

Respuesta :

Answer:

O2 + 4e- -> 2O2-

Explanation:

You have to start by assigning the oxidation numbers, which eventually will lead to every atom of oxygen taking 2 electrons and every molecule of oxygen will take 4 electrons.

(you can ignore this explanation, my answer wasn't long enough).

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