Answer:
A. [tex]2x^2y\sqrt[3]{7xy^2}[/tex]
Step-by-step explanation:
When given the following problem,
[tex]\sqrt[3]{56x^7y^5}[/tex]
The problem asks one to find the cube root of the value under the radical. The cube root of a number is essentially a value that must be multiplied by itself three times to get the result under the radical. An easy way to do this is to prime factorize the value under the radical sign. This will allow one to see the components of the number, thus making it easier to take value out of the radical;
[tex]=\sqrt[3]{7*2^3x^7y^5}[/tex]
Now divide each of the exponents by (3), write the whole result outside the radical, and the remainder under the radical,
[tex]=2x^2y\sqrt[3]{7xy^2}[/tex]
