First we find the slope of the line 2x−3y+8=0 by placing it into slope intercept form:
2x−3y+8=0
⇒−3y=−2x−8
⇒3y=2x+8
⇒y=
3
2
x+
3
8
Therefore, the slope of the line is m=
3
2
.
Now since the equation of the line with slope m passing through a point (x
1
,y
1
) is
y−y
1
=m(x−x
1
)
Here the point is (2,3) and slope is m=
3
2
, therefore, the equation of the line is:
y−3=
3
2
(x−2)
⇒3(y−3)=2(x−2)
⇒3y−9=2x−4
⇒2x−3y=−9+4
⇒2x−3y=−5
Hence, the equation of the line is 2x−3y=−5.
Answer:
y=2/3x-11/3
Step-by-step explanation:
Hi there!
We are given the equation 2x-3y=9 and we want to write an equation that is parallel to it and that passes through (4,-1)
Parallel lines have the same slopes
So we need to first find the slope of 2x-3y=9
We can do this by converting the equation of the line from standard form (ax+by=c where a, b, and c are integers) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept)
To do this, we need to isolate y on one side
2x-3y=9
subtract 2x from both sides
-3y=-2x+9
divide both sides by -3
y=2/3x-3
as 2/3 is in the place where m is, 2/3 is the slope of the line
It's also the slope of the line parallel to it that passes through (4,-1).
Here's the equation of that line so far:
y=2/3x+b
now we need to find b
as the line will pass through the point (4,-1), we can 4 as x and -1 as y in order to solve for b
-1=2/3(4)+b
multiply
-1=8/3+b
subtract 8/3 to both sides
-11/3=b
Substitute -11/3 as b into the equation
y=2/3x-11/3
There's the equation
Hope this helps!
