Step-by-step explanation:
"must be used first" is a very hard phrasing. multiplication is commutative.
and I am not sure that the problem is stated correctly.
I read here
(i×y²) to the power of 1/3.
i is the imaginary constant sqrt(-1) ?
exponents brought themselves to the power of something else multiply.
e.g.
[tex]({2}^{3})^{4} = {2}^{12} [/tex]
exponents in multimedia expressions of the same base simply add up.
e.g.
[tex] {2}^{3} \times {2}^{4} = {2}^{7} [/tex]
a negative exponent means that the expression with the same positive exponent is just at the bottom of a division.
e.g.
[tex] {2}^{ - 3} = 1 \div {2}^{3} [/tex]
and a fraction as exponent specifies a root to be taken.
e.g
[tex] {2}^{1 \div 3} = \sqrt[3]{2} [/tex]
so, I would do all the exponent multiplications to simplify the expression.
[tex] \sqrt[3]{i \times {y}^{2} } = ({i \times {y}^{2} })^{1 \div 3} = [/tex]
[tex] = ( { - 1}^{1 \div 2} \times {y}^{2} ) ^{1 \div 3} [/tex]
1/2 × 1/3 = 1/6
2 × 1/3 = 2/3
[tex] = { - 1}^{1 \div 6} \times {y}^{2 \div 3} = \sqrt[6]{ - 1} \times \sqrt[3]{ {y}^{2} } [/tex]
so, as we can see, we can move freely from multiplying the fraction exponents to converting them into root expressions and vice versa.
