Answer:
The width of the field is 35 meters.
Step-by-step explanation:
Recall that the perimeter of a rectangle is given by:
[tex]\displaystyle P = 2(w+\ell)[/tex]
Where w is the width and l is the length of the rectangle.
We know that the perimeter is 150 meters. Thus:
[tex]150=2(w+\ell)[/tex]
Divide both sides by two:
[tex]75=w+\ell[/tex]
We are given that the length is five meters longer than the width. So:
[tex]\ell = w+5[/tex]
Substitute:
[tex]75=w+(w+5)[/tex]
Combine like terms:
[tex]75=2w+5[/tex]
Subtract five from both sides:
[tex]70=2w[/tex]
And divide both sides by two. Hence:
[tex]w=35[/tex]
Thus, the width of the rectangular field is 35 meters.
