Answer:
[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]
Step-by-step explanation:
Given
[tex]x^3y^{-7}[/tex]
Required
The equivalent
We have:
[tex]x^3y^{-7}[/tex]
Apply the following rule of exponents
[tex]a^{-b} = \frac{1}{a^b}[/tex]
So, we have:
[tex]x^3y^{-7} = x^3 * \frac{1}{y^7}[/tex]
[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]
