Answer:
[tex]\frac{\sqrt{2} }{2}[/tex]
Step-by-step explanation:
45 - 45 - 90 Triangles
When one leg = x, the hypotenuse = x[tex]\sqrt{2}[/tex]
So, if the hypotenuse is 1, then divide by [tex]\sqrt{2}[/tex] to get the leg.
[tex]\frac{1}{\sqrt{2} }[/tex] rationalize denominator.
[tex]\frac{1}{\sqrt{2}}[/tex] × [tex]\frac{\sqrt{2}}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2}}{\sqrt{2} \sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{\sqrt{4}}[/tex] = [tex]\frac{\sqrt{2}}{2}[/tex]
