Answer:
x = 0, π/3, 2π/3, π, 4π/3, 5π/3
Step-by-step explanation:
4cos^4(x) – 5cos^2(x) + 1 = 0
(4cos^2(x) - 1)(cos^2(x) - 1) = 0
When 4cos^2(x) - 1 = 0
cos^2(x) = 1/4
cos x = +/-1/2
so x = π/3, 2π/3, 4π/3, 5π/3.
When cos^2x - 1 = 0
cos x = +/- 1
x = 0, π.
x
Answer: did you do the question be for this question on the performance task if so can you help me plz
Step-by-step explanation:
