Answer:
D
Step-by-step explanation:
Evaluate the fractions inside the absolute value
2 [tex]\frac{5}{6}[/tex] + [tex]\frac{7}{4}[/tex] ( change mixed number to improper fraction )
= [tex]\frac{17}{6}[/tex] + [tex]\frac{7}{4}[/tex] ( the LCM of 6 and 4 is 12 ) , then
= [tex]\frac{17(2)}{6(2)}[/tex] + [tex]\frac{7(3)}{4(3)}[/tex]
= [tex]\frac{34}{12}[/tex] + [tex]\frac{21}{12}[/tex] ( add the numerators, leaving the common denominator )
= [tex]\frac{55}{12}[/tex]
= 4 [tex]\frac{7}{12}[/tex] → D
