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If the woman in the picture below measured the angle of elevation from herself to the top of castle and found it to be 64 degrees, and she also measured the distance from herself to the base of the castle as being 124 meters, what would the height of the castle be? (round to the nearest whole meter.)

If the woman in the picture below measured the angle of elevation from herself to the top of castle and found it to be 64 degrees and she also measured the dist class=

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abidemiokin

Answer:

254m

Step-by-step explanation:

The setup will be in form of a right triangle. Hence;

The angle of elevation = 64degrees

distance from herself to the base of the castle = 124 meters (Adjacent)

Required

Height of the castle (Opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 64 = H/124

H = 124tan64

H = 124(2.05030)

H = 254.23

H ≈ 254m

Hence the height of the castle to the nearest whole meters is 254metres

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