What is the solution to this equation?
log_8 16 + 2log_8x =2

The value of x for the given equation [tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2 will be 2 so option (B) must be correct.
The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.
In another word, a logarithm is a different way to denote any number.
Given the equation
[tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2
We know that,
xlogb = log[tex]b^{x}[/tex]
So,
2[tex]log_{8}[/tex](x) = logx²
For the same base
logA + logB = log(AB)
So,
[tex]log_{8}[/tex](16) + [tex]log_{8}[/tex](x)² = 2
[tex]log_{8}[/tex](16x²) = 2
We know that
[tex]log_{a}[/tex](b) = c ⇒ b = [tex]a^{c}[/tex]
so,
[tex]log_{8}[/tex](16x²) = 2 ⇒ 8² = 16x²
x = 2 hence x = 2 will be correct answer.
For more about logarithm
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