The reaction that will take place is:
CuO + H₂SO₄ → CuSO₄ + H₂O (balanced)
Amount of Sulphuric acid provided:
we have 500 mL of a 0.5 molar solution of Sulphuric acid (1 cm³ = 1mL)
We know that molarity is found with the formula:
Molarity = Number of Moles / Volume (in L)
let's plug the given values
0.5 = Number of moles / 0.5 L
Number of moles = 0.25 moles [multiplying both sides by 0.5]
Amount of CuO reacted:
from the balanced equation, we know that CuO reacts with H₂SO₄ in a 1:1 ratio (1 mole of CuO reacts with 1 mole of H₂SO₄)
so 0.25 moles of H₂SO₄ (present in the solution) will react with 0.25 moles of CuO
Mass of 0.25 moles of CuO:
molar mass of CuO = 80 grams/mol (approx.)
we are aware of the relation:
Number of moles = Given mass / Molar mass
plugging the values we have:
0.25 = Mass / 80
Mass = 20 grams [multiplying both sides by 80]
Hence 20 grams of CuO will react
