suppose two soccer teams consist of players with a combined average height of 66 inches. if team a has an average height of 68 inches and has twice as many members as team b, what is the average height of team b

Respuesta :

Answer:

The average height of team b is 62 inches.

Step-by-step explanation:

Mean:

The mean of a data-set is the sum of all values in the data-set divided by the number of values, that is:

[tex]M = \frac{s}{n}[/tex]

Sum:

Team a: Mean of 68 inches, 2x members.

Team b: Mean of y inches, x members.

So

[tex]s = 68*2x + yx = x(136 + y)[/tex]

Number of athletes:

[tex]n = 2x + x = 3x[/tex]

What is the average height of team b?

[tex]66 = \frac{x(136+y)}{3x}[/tex]

[tex]66 = \frac{136 + y}{3}[/tex]

[tex]136 + y = 198[/tex]

[tex]y = 198 - 136 = 62[/tex]

The average height of team b is 62 inches.