sand falls from an overhead bin and accumulates in a conical pile with a radius that is always four times its height. suppose the height of the pile infcreases at a rate of 1cm/s when the pile is 12 cm hight. at what rate is the sand leaving the bin at that instant

Respuesta :

Answer:

[tex]\frac{dv}{dt} =7239.168 cm/sec[/tex]

Step-by-step explanation:

From the question we are told that:

Rate [tex]\frac{dh}{dt}=1cm[/tex]

Height [tex]h=12cm[/tex]

Radius [tex]r=4h[/tex]

Generally the equation for Volume of Cone is mathematically given by

[tex]V=\frac{1}{3}\pi r^2h[/tex]

[tex]V=\frac{1}{3}\pi (4h)^2h[/tex]

Differentiating

[tex]\frac{dv}{dt} =\frac{16}{3}\pi3h^2\frac{dh}{dt}[/tex]

[tex]\frac{dv}{dt} =\frac{16}{3}*3.142*3*12^2*1[/tex]

[tex]\frac{dv}{dt} =7239.168 cm/sec[/tex]