Answer:
0.045 = 4.5% probability a selected component is defective
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Probability of a defective component:
4% of 50%(shipment I)
5% of 50%(shipment II). So
[tex]p = 0.04*0.5 + 0.05*0.5 = 0.045[/tex]
0.045 = 4.5% probability a selected component is defective
