Complete Question
A charged particle of mass 0.0040 kg is subjected to a 40-T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.10 m at a speed of 20m/s, what is the magnitude of the charge on the particle?
Answer:
[tex]q=0.020C[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=0.004kg[/tex]
Magnetic field [tex]B=40-T[/tex]
Radius [tex]r=0.10m[/tex]
Speed [tex]v= 20m/s[/tex]
Generally the equation for Radius of a circular path is mathematically given by
[tex]r=\frac{p}{qB}[/tex]
Where
[tex]p=mv[/tex]
Therefore
[tex]q=\frac{mv}{rB}[/tex]
[tex]q=\frac{0.004kg*20m/s}{0.1*40}[/tex]
[tex]q=0.020C[/tex]
