Answer:
[tex]v(t) = 2t - 5[/tex]
Step-by-step explanation:
Given
[tex]s(t) = t^2 - 5t + 1[/tex]
Required
The speed of the particle
To do this, we simply differentiate the position function
i.e.
[tex]v(t) = s'(t)[/tex]
So, we have:
[tex]s(t) = t^2 - 5t + 1[/tex]
Differentiate
[tex]s'(t) = 2t - 5 + 0[/tex]
[tex]s'(t) = 2t - 5[/tex]
So, the speed function is:
[tex]v(t) = 2t - 5[/tex]