For any triangle ABC, The correct option the given triangle is B. m∠B=47, m∠C=28, b=28.
What is law of sines?
For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,
we have, by law of sines,
[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]
Remember that we took,
[tex]\dfrac{\sin(angle)}{\text{length of the side opposite to that angle}}[/tex]
We have been given angle A = 105 degrees and side a = 37, side c = 18.
[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle C}{c}\\\\\dfrac{sin\angle 105}{37} = \dfrac{sin\angle C}{18}\\\\sin\angle C = \dfrac{sin\angle 105}{37} \times 18 \\\\sin\angle C = 28[/tex]
By angle sum property;
A + B + C = 180
105 + 28 + B = 180
B = 180 - 133
B = 47
Therefore,
[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b}\\\\\dfrac{sin\angle 105}{37} = \dfrac{sin\angle 47}{b} \\\\b = 28[/tex]
Hence, the correct option the given triangle is B. m∠B=47, m∠C=28, b=28.
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