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How many joules are required to convert 16.5 g g of ice at 0.0 ∘C ∘ C to liquid water at 32.0 ∘C ∘ C ? The heat of fusion of water is 334 J J /g g .

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asuwafohjames

Answer:

5511 J

Explanation:

Applying,

Q = Cm.................... Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

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