Answer:
If the son’s age is x, the father’s age is 2x.
If the son’s age is x, the father’s age is 2x.Ten years ago:
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 52
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 52
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 24
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48
If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.
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