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How many grams of calcium chloride are needed to produce 10.0 g of potassium chloride?

CaCl2(aq) + K2CO3(aq) → 2 KCl(aq) + CaCO3(aq)

Respuesta :

mwabamwaba2004

Answer:

11.1g

Explanation:

since the equation is already balanced just drop down the elements you will work with and use the mole to mole ratios

Cacl2 : 2Kcl

1 : 2

since potassium chloride has alot of information find it's moles

number of moles=mass/molecular mass

=10g/74.5

=0.13g/mol

now use the mole to mole ratios to find the number of moles of calcium chloride

1 : 2

x:0.13

2x/2=0.13/2

x=0.067g/mol of cacl2

then you can calculate the mass of calcium chloride

m=n×mm

=0.067×111

=7.4g

I hope this helps

Eduard22sly

The mass of calcium chloride, CaCl₂ needed to produce 10 g of potassium chloride, KCl is 7.45 g

We'll begin by calculating the mass of CaCl₂ that reacted and the mass of KCl produced from the balanced equation.

CaCl₂ + K₂CO₃ —> 2KCl + CaCO₃

Molar mass of CaCl₂ = 40 + (35.5 × 2) = 111 g/mol

Mass of CaCl₂ = 1 × 111 = 111 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mass of KCl from the balanced equation = 2 × 74.5 = 149 g

From the balanced equation above,

149 g of KCl were produced by 111 g of CaCl₂.

Finally, we shall determine the mass of CaCl₂ needed to produce 10 g of KCl. This can be obtained as follow:

From the balanced equation above,

149 g of KCl were produced by 111 g of CaCl₂.

Therefore,

10 g of KCl will be produce by = (10 × 111) / 149 = 7.45 g of CaCl₂.

Thus, 7.45 g of CaCl₂ were obtained from the reaction.

Learn more about stoichiometry: https://brainly.com/question/15858344