Answer:
v = sqr(t^(1/2)) - 4 * s / d^4
K = 8 * x^3 - 2 * y^6 / 5 * d + e^4
Explanation:
Given
[tex]v = \ \sqrt{t} ^{2} - 4s \div {d}^{4}[/tex]
[tex]K = {8}{x}^{3} - {2}{y}^{ 6} \div {5}{d}+ {e}^{4}[/tex]
Required
The equivalent in Q Basic
To solve this, we use the following rules:
+ , - and * are written as + , - and *
[tex]\div[/tex] is written as /
^ stands for raise to power
SQR is used for square
^(1/2) stands for square root.
So, the equivalents of the above statements are:
v = SQR(t^(1/2)) - 4 * s / d^4
K = 8 * x^3 - 2 * y^6 / 5 * d + e^4
