Delta math need help

Answer:
2.6
Step-by-step explanation:
We'll use the Pythagoras theorem to solve this, which states that in a right angle triangle:
h^2 = a^2 + b^2
4^2 = 3^2 +b^2
16= 9 +b^2
16-9= b^2
7= b^2
(take square root in both sides)
b= 2.65
round to nearest 10th = 2.6
answer by Gauthmath
Answer:
Missing side is 2.6
3^2 + x^2 = 4^2
9 + x^2 = 16
-9 -9
x^2 = 7
([tex]\sqrt{x}[/tex])^2 = [tex]\sqrt{7}[/tex]
x = 7
Find the approximation o the square root of 7 in fractions then carry out the long division.
Or
Approx. is 2 3/5 which equals 2 6/10 which equals 2.6