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Please hurry I will mark you brainliest

It's a hot summer
day and the icecream truck is on it's way. The driver gives you two options:
1) You can have a cone that is doubled in radius but the same height as a regular cone.

OR

2) You can have a cone that is doubled in height but the same radius as a regular cone.

Which would you choose and why?
You can explain it or attach a picture of your work.

Respuesta :

Answer:

Volume of a cone - πr^2(h/3)

Step-by-step explanation:

If radius doubled - π2r^2(h/3)

If height doubled - πr^2(2h/2)

Let's assume r and h to be 1.

Radius doubled = 2π(1/3) = 2.09439510239 (volume)

Height doubled = π(2/3) = 2.09439510239 (volume)

If radius and height equal for 1, does it mean it is equal for other values too?

Let's use 2 instead of 1 and find out:

8π(2/3) - Option 1

8π(2/3) - Option 2

Both are the same...

Answer:

2x on the radius...

Vol = [tex]\frac{1}{3} \pi r^{2} h[/tex]  

[tex]\frac{1}{3} \pi[/tex] is constant (in this story)

[tex](2r)^{2}[/tex]  vs. 2h   ... the     [tex](2r)^{2}[/tex] will most likely be bigger...

I say most likely because if the cone radius was super small and

the height was super long (like a straw, or a piece of spaghetti)

then the 2x on the height actually can be better  

Step-by-step explanation:

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