Answer:
Y =4X -3
Step-by-step explanation:
x1 y1 x2 y2
1 1 -2 -11
(Y2-Y1) (-11)-(1)= -12 ΔY -12
(X2-X1) (-2)-(1)= -3 ΔX -3
slope= 4
B= -3
Y =4X -3
Answer:
y=4x-3
Step-by-step explanation:
Hi there!
We are given the points (1,1) and (-2, -11) and we want to write the equation of the line in slop-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
So let's find the slope of the line
The formula for the slope calculated from two points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
We have everything we need to calculate the slope, let's just label the points to avoid confusion
[tex]x_1=1\\y_1=1\\x_2=-2\\y_2=-11[/tex]
Now substitute those values into the formula
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{-11-1}{-2-1}[/tex]
Subtract
m=[tex]\frac{-12}{-3}[/tex]
Divide
m=4
So the slope of the line is 4
Here is the equation of the line so far:
y=4x+b
We need to find b
As the equation passes through both (1,1) and (-2, -11), we can plug either one of them into the equation to solve for b
Taking (1,1) will give us this:
1=4(1)+b
Multiply
1=4+b
Subtract 4 from both sides
-3=b
Substitute -3 as b into the equation
y=4x-3
Hope this helps!
