The graph of a line is shown below. What is the equation of the line, in slope-intercept form, that is parallel to this line and has a y-intercept of 1?

Answer:
[tex]y = - \frac{3}{2} x + 1[/tex]
Step-by-step explanation:
Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.
Parallel lines have the same slope. Let's find the slope of the given line.
Given points: (-2, 0) and (0, -3)
[tex]\boxed{slope = \frac{y1 - y2}{x1 - x2} }[/tex]
slope of given line
[tex] = \frac{0 - ( - 3)}{ - 2 - 0} [/tex]
[tex] = \frac{0 + 3}{ - 2} [/tex]
[tex] = - \frac{3}{2} [/tex]
[tex]y = - \frac{3}{2} x + c[/tex]
Given that the y- intercept is 1, c= 1.
[tex]y = - \frac{3}{2} x + 1[/tex]