Given :
Seena’s mother is 4 times as old as Seena. After 5 years her mother will be 3 times as old as she will be then .Find their present ages.
Solution :
✧ Let us assume :
Seena's age be x
Her mother's age be 4x
✧ After 5 years :
Seena's age = x + 5
Her mother's age = 4x + 5
✧ Ratio of age after 5 years :
Seena's mother = 3
Seena's ratio = 1
Hence, the equation is :
[tex] \looparrowright\frak{ \frac{4x + 5}{x + 5} = \frac{3}{1} }[/tex]
By cross multiplying we get
[tex] \looparrowright \frak{3(x + 5) = 4x + 5}[/tex]
[tex] \looparrowright \frak{3x + 15 = 4x + 5}[/tex]
[tex] \looparrowright \frak{x = 10}[/tex]
Hence, the ages are
Seena's age = x = 10 yrs
Her mother's age = 4x = 4 × 10 = 40 years
∴ Seena's age is 10 and her mother's is 40 respectively
