Answer:
Solution given:
at first
volume[tex]V_{1}=120.0ml[/tex]
pressure [tex]P_{1}=0.75atm[/tex]
temperature [tex]T_{1}=22+273=295°K[/tex]
after increasing temperature and pressure
volume[tex]V_{2}=xml[/tex]
pressure [tex]P_{2}=1.25atm[/tex]
temperature [tex]T_{2}=70+273=343°K[/tex]
now
By using Combined gas equation
[tex]\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}[/tex]
substituting value
[tex]\frac{0.75*120}{295}=\frac{1.25*x}{343}[/tex]
0.305=5x/1372
Doing criss cross multiplication
5x=0.305*1372
x=418.46/5
x=83.69ml
x=84ml
the volume will be 84ml
