Answer:
[tex]3x^2-3x\left(x-2\right)-12=0[/tex]
[tex]3x^2-3x\left(x-2\right)-12+12=0+12 \longleftarrow (\mathrm{Add\:}12\mathrm{\:to\:both\:sides})[/tex]
[tex]3x^2-3x\left(x-2\right)=12[/tex]
[tex]-3x\left(x-2\right)=-3xx-\left(-3x\right)\cdot \:2[/tex]
[tex]=-3xx+3\cdot \:2x[/tex]
[tex]-3xx+3x^{2}[/tex]
[tex]=3x^{1+1}[/tex]
[tex]=3x^2[/tex]
[tex]3\cdot \:2x=6x[/tex]
[tex]=-3x^2+6x[/tex]
[tex]3x^2-3x^2+6x=12\Longleftarrow Add\:similar\:elements[/tex]
[tex]6x=12[/tex]
[tex]\frac{6x}{6}=\frac{12}{6} \Longleftarrow Divide[/tex]
[tex]x=2[/tex]
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OAmalOHopeO
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