Given:
If x, y, and z are positive integers, then
[tex]2^x\times 3^y\times 5^z=54000[/tex]
To find:
The value of [tex]x+y+z[/tex].
Solution:
First we need to find the prime factors of 54000.
[tex]54000=2\times 2\times 2\times 2\times 3\times 3\times 3\times 5\times 5\times 5[/tex]
[tex]54000=2^4\times 3^3\times 5^3[/tex] ...(i)
We have,
[tex]54000=2^x\times 3^y\times 5^z[/tex] ...(ii)
On comparing (i) and (ii), we get [tex]x=4,y=3,z=3[/tex].
The sum of [tex]x,y,z[/tex] is:
[tex]x+y+z=4+3+3[/tex]
[tex]x+y+z=10[/tex]
Therefore, the value of [tex]x+y+z[/tex] is 10.
