Given:
Amplitude = 21
Vertical shift = 19 units down
To find:
The maximum and the minimum value.
Solution:
The general form of sine function is:
[tex]y=A\sin (Bx+C)+D[/tex]
Where, |A| is amplitude, [tex]\dfrac{2\pi}{B}[/tex] is period, [tex]-\dfrac{C}{B}[/tex] is phase shift and D is the vertical shift.
Here,
[tex]Maximum=D+A[/tex]
[tex]Minimum=D-A[/tex]
We have,
Amplitude: [tex]A = 21[/tex]
Vertical shift: [tex]D=-19[/tex]
Negative sign means shifts downwards.
Now,
[tex]Maximum=D+A[/tex]
[tex]Maximum=-19+21[/tex]
[tex]Maximum=2[/tex]
And,
[tex]Minimum=D-A[/tex]
[tex]Minimum=-19-21[/tex]
[tex]Minimum=-40[/tex]
Therefore, the minimum value is -40 and the maximum value is 2.
