Answer:
y = [tex]\frac{20}{9}[/tex]
Step-by-step explanation:
Since the figures are similar then the corresponding sides are in proportion, that is
[tex]\frac{JH}{PQ}[/tex] = [tex]\frac{FM}{ST}[/tex] , substitute values
[tex]\frac{6}{4}[/tex] = [tex]\frac{7}{3y-2}[/tex] ( cross- multiply )
6(3y - 2) = 28
18y - 12 = 28 ( add 12 to both sides )
18y = 40 ( divide both sides by 18 )
y = [tex]\frac{40}{18}[/tex] = [tex]\frac{20}{9}[/tex]
Answer:
20/9
Step-by-step explanation:
since the 2 are similar,
JH/PQ = FM/ST
6/4 = 7/(3y-2)
6(3y-2) = 7*4
18y-12=28
18y = 40
y = 40/18 = 20/9 = 2 2/9
