contestada

[tex]\sqrt{a^{2}+ab+b^{2}} +\sqrt{ a^{2}+ac+c^{2} } \geq \sqrt{ b^{2}+bc+c^{2}[/tex]

Respuesta :

msm555

Answer:

Solution given:

[tex]\sqrt{a^{2}+ab+b^{2}} +\sqrt{a^{2}+ac+c^{2}}+ \sqrt{ b^{2}+bc+c^{2}}[/tex]

[tex]\sqrt{(a+b)²} +\sqrt{ (a+c)² }+\sqrt{(b+c)²}[/tex]

a+b+a+c+b+c

2a+2b+2c

2(a+b+c)

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