Answer:
Step-by-step explanation:
We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so
3L + 5s = 88
12L + 2s = 235 according to the other information given.
Solve the first equation for either L or s. I'll solve for L, just because:
3L = 88 - 5s and
L = [tex]\frac{88}{3}-\frac{5}{3}s[/tex] and sub that into the second equation for L:
[tex]12(\frac{88}{3}-\frac{5}{3}s)+2s=235[/tex] and if you distribute the 12 into the parenthesis you'll simplify it down a bit to
352 - 20s + 2s = 235 and combine like terms:
-18s= -117 so
s = 6.5 kg and plug that in to solve for L:
L = [tex]\frac{88}{3}-\frac{5}{3}(6.5)[/tex] and
L = 18.5 kg
