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Ann and Bob are carrying a 18.5 kg table that is 2.25 m long. A 8.33 kg box sits on the table 0.750 m from Ann. How much lift force does Ann exert? Use 9.80 for gravity and answer in Newtons

Respuesta :

Answer:

F = 118 N

Explanation:

Assume Ann and Bob lift at their respective ends of the table

Sum moments about Bob's position to zero.

Let F be Ann's upward force

F[2.25] - 18.5(9.80)[2.25 / 2] - 8.33(9.80)[0.750] = 0

F = 117.86133333...  

Cricetus

The lift force exert by Bob will be "117.9 N".

Given:

  • Mass of table, [tex]m_t = 18.5 \ kg[/tex]
  • Mass of box, [tex]m_b = 8.33 \ kg[/tex]
  • Length of table, [tex]2.25 \ m[/tex]
  • Length of box, [tex]0.75 \ m[/tex]

The weight of table will be:

→ [tex]W_t = m_t g[/tex]

        [tex]= 18.5\times 9.8[/tex]

        [tex]= 181.3 \ N[/tex]

Now,

→ [tex]\sum M_A_{nn} = -81.634\times 0.750-181.3\times 1.125+R_{bob}\times 1.125[/tex]

or,

→ [tex]R_{bob} = \frac{61.2255+203.9625}{2.25}[/tex]

          [tex]= \frac{265.188}{2.25}[/tex]

          [tex]= 117.9 \ N[/tex]

Thus the above answer is right.

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