speziuzbek speziuzbek

25-07-2021
Mathematics

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Hi,there,can you solve this equation.
4x*sqrt(2x-x²)=2x-1

Respuesta :

loconte loconte

25-07-2021

Answer:

Step-by-step explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 = 4x^2 -4x + 1

[tex]-16x^4+32x^3-4x^2+4x-1=0\\[/tex]

[tex]x = 1.92887[/tex]

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