Given:
The equation is:
[tex]5x-2=4+2x[/tex]
To find:
The number that belongs in the green box and another box.
Solution:
We have,
[tex]5x-2=4+2x[/tex]
Subtracting 2x from both sides, we get
[tex]5x-2-2x=4+2x-2x[/tex]
[tex]3x-2=4[/tex]
Adding 2 on both sides, we get
[tex]3x-2+2=4+2[/tex]
[tex]3x=6[/tex]
We need to divide both sides by 3 to isolate the variable x.
On dividing both side by 3, we get
[tex]\dfrac{3x}{3}=\dfrac{6}{3}[/tex]
Therefore, the missing values are 3 and 3, and the required equation is [tex]\dfrac{3x}{3}=\dfrac{6}{3}[/tex].
