Answer:
Step-by-step explanation:
In this question, the sample space contains 8 elements and has been given as;
HHT HHH THH HTH HTT TTT TTH THT
1. For event A:
Outcomes of alternating tail and head = THH HTH HTT THT
= 4 outcomes
Pr(alternating tail and head (with either coming first)) = [tex]\frac{4}{8}[/tex]
= [tex]\frac{1}{2}[/tex]
2. For event B:
Outcomes of no tails on the first two tosses = HHT HHH
= 2 outcomes
Pr (No tails on the first two tosses) = [tex]\frac{2}{8}[/tex]
= [tex]\frac{1}{4}[/tex]
For event C:
Outcomes of a tail on both the first and the last tosses = THT TTT
= 2 outcomes
Pr(A tail on both the first and last tosses) = [tex]\frac{2}{8}[/tex]
= [tex]\frac{1}{4}[/tex]