[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{x_1+x_2}{2}_\dfrac{y_1+y_2}{2}\right)[/tex]
[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{10-4}{2},\dfrac{-3-9}{2}\right)[/tex]
[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{6}{2},\dfrac{-12}{2}\right)[/tex]
[tex]\\ \rm\hookrightarrow (x,y)=(3,-6)[/tex]
Answer:
(3, - 6 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = (10, - 3) and (x₂, y₂ ) = (- 4, - 9) , then
midpoint = ( [tex]\frac{10-4}{2}[/tex] , [tex]\frac{-3-9}{2}[/tex] ) = ( [tex]\frac{6}{2}[/tex] , [tex]\frac{-12}{2}[/tex] ) = (3, - 6 )
