272 students enrolled in a freshman-level chemistry class. By the end of the semester, 7 times the number of students passed as failed. Find the number of students who passed, and the number of students who failed.

Respuesta :

Answer:

Let x is number of students falled.

Then 6x is number of students passed. So, 6x + x = 273; 7x = 273, x = 39

Answer: 39 students falled, 273 - 39 = 234 students passed

Step-by-step explanation:

The number of students who passed is 234 and the number of students who failed is 39.

To find number of students who passed, and the number of students who failed.

What is arithmetic?

The branch of mathematics dealing with the properties and manipulation of numbers.

Given that:

students enrolled in a freshman-level chemistry class=272

By the end of the semester, 7 times the number of students passed as failed.

Let x is number of students failed.

Then 6x is number of students passed.

So, 6x + x = 273

7x = 273,

∴x = 39

number of students passed= 273 - 39 = 234

So, the number of students who passed is 234 and the number of students who failed is 39.

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