amritanshwiv
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In a single throw of two coins,find the probability of getting each of the following:-)
i.)Tails on both
ii)Tails at least on one
iii)Tails on one
iv)No tails

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Respuesta :

Step-by-step explanation:

1.) two tails :

total no. of outcomes possible is TT,TH,HT,HH

no. of outcomes with TT is 1

p( tails on both) = 1/4

2.) tails at least one:

no. of outcomes with one tails atleast is 3 (TT,th,ht,)

p( atelast one tails) = 3/4

3.) tails on one

no. of outcomes with one tails at most is 2 (th,ht)

p( atmost one tails) is 2/4= 1/2

4. no tails

no. of outcomes with no tails is 1(HH)

p( no tails) = 1/4

hope it's understandable.

Answer:

1.) two tails :

total no. of outcomes possible is TT,TH,HT,HH

no. of outcomes with TT is 1

p(tails on both) = 1/4

2.) tails at least one:

no. of outcomes with one tails atleast

is 3 (TT,th,ht,)

p(atelast one tails) = 3/4

3.) tails on one

no. of outcomes with one tails at most is 2 (th,ht)

p(atmost one tails) is 2/4= 1/2

4. no tails

no. of outcomes with no tails is 1(HH)

p(no tails) = 1/4

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