Answer:
Choice D. There is exactly one plane that contains the three ducks: [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex].
Step-by-step explanation:
The three points [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are distinct since each of the three points represents a different duck.
There's only one line through two distinct points in a 2D cartesian plane.
Likewise, given two distinct points ([tex]\sf G[/tex] and [tex]\sf J[/tex]) in a 3D space, there would be only one line two the two points.
Assume that plane [tex]\sf L[/tex] represents the plane that contains the surface of the lake.
A line is in a plane if and only if all points on that line are in the said plane.
Point [tex]\sf G[/tex] is on the line that contains [tex]\sf G\![/tex] and [tex]\sf H[/tex]. However, since point [tex]\!\sf G[/tex] denotes the flying duck, this point would not be in [tex]\sf L[/tex] (the plane that contains the surface of the lake.)
Hence, the line that contains [tex]\sf G\![/tex] and [tex]\sf H\![/tex] would not be in plane [tex]\sf L\![/tex].
Given three distinct points in a 3D space, there would be exactly one plane that contains the three points.
Hence, three points in a 3D space would not be non-coplanar.
In this question, point [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are all distinct. Hence, there would be exactly one plane that contains these three points.
