907girt 907girt
  • 24-08-2021
  • Mathematics
contestada

find the zeros of f(x)=-x^2+6x+27

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christopherball72
christopherball72 christopherball72
  • 24-08-2021

Answer:

Zeroes of this function are -3 and 9.

Step-by-step explanation:

Using quadratic formula we have:

(-6 +- [tex]\sqrt{6^{2}-4(-1)(27) }[/tex]) / 2(-1)

= -3, 9

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