Find the root(s) or zero(s) of the function.

Answer:
-1/2 , 3
Step-by-step explanation:
In order to find the roots of the function 2x² - 5x - 3
We have to solve the quadratic equation :
2x² - 5x - 3 = 0
Calculating the discriminant Δ :
Δ = b² - 4ac
= (-5)² - 4(2)(-3)
= 25 + 24
= 49
Then
√Δ = √49 = 7
Determining the Zeros :
[tex]x=\frac{-b+\sqrt{b^{2}-4ac} }{2a} = \frac{5+7} {2 \times (2)} =\frac{12}{4} =3[/tex]
or
[tex]x=\frac{-b-\sqrt{b^{2}-4ac} }{2a} = \frac{5-7} {2 \times (2)} =\frac{-2}{4} =\frac{-1}{2}[/tex]