A polynomial function h(x) has a zero of x = 2 + 7i with a multiplicity of one. Certain values of h(x) are given in the following table. x h(x) –5 0 –2 3 –1 –1 1 2 4 0 7 6 10 0 If every real x-intercept of h(x) is shown in the table and each has a multiplicity of one, what is the degree of h(x)? 3

Respuesta :

Degree of h(x) is 5 because there are 5 x intercepts

Given :

The function h(x) has a zero of x = 2 + 7i with a multiplicity of one.

Every x intercept has multiplicity 1

Explanation

x intercept x=2+7i has multiplicity one

For complex intercepts occurs in pairs

So another x intercept is x=2-7i

From the given table , when h(x) is 0 then x is the x intercepts

other x intercepts from the given table are  -5, 4,10

There are 5 x intercepts with multiplicity one

h(x) has 5 x intercepts . so , the degree of h(x) is 5

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Answer:

5

Step-by-step explanation:

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