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If I have 4.9 moles of gas at a pressure of 2.0 atm and a temperature of 56 Celsius, what is the volume of the cantainer that the gas is
in? (R=0.0821 L*atm/mol*K)

Respuesta :

rspill6

Answer:  132 liters. or 130 liters with 2 sig figs.

Explanation:  Use the ideal gas law:  PV = nRT

We want V, so rewrite and plug in data:

Temperture must be in Kelvin (add 273.15 to

V = (nRT)/P

V = (4.9 moles)*(0.0821 L*atm/molK)*(328.2K)/(1atm)

V = 132 liters (3 sig figs).  130 liters with 2 sig figs