Answer:
P(3 , 0)
Step-by-step explanation:
(x₁, y₁) = A(-3,-3) ;(x₂ , y₂) B(5, 1)
m : n = 3 : 1
[tex]P \left( \dfrac{mx_{2}+nx_1}{m+n},\dfrac{my_{2}+ny_{1}}{m+n} \right)\\\\P \left (\dfrac{5*3+(-3)*1}{3+1},\dfrac{3*1+1*(-3)}{3+1} \right)\\\\\\=P \left(\dfrac{15-3}{4},\dfrac{3-3}{4} \right)\\\\\\= P \left(\dfrac{12}{4},\dfrac{0}{4} \right)\\\\\\= P\left(3 , 0 \right)[/tex]
