1/5 is the dilution of reagent A in water.
Explanation:
- The dilution factor of the diluted solution is determined by dividing the final volume of the diluted solution by the volume of the undiluted solution.
[tex]D.F.=\frac{V_f}{V_i}[/tex]
Where:
D.F = Dilution factor
[tex]V_f[/tex] = Final volume of the diluted solution
[tex]V_i[/tex]= Initial volume of the undiluted solution
- And the dilution is represented as 1 : D.F.
Given:
4 parts of the reagent and 16 parts of water are mixed together to form a diluted solution.
To find:
The dilution of reagent A in water
Solution:
Parts of reagent A =[tex]V_i = 4[/tex]
Parts of water = 16
Final volume of solution = [tex]V _f = 4 + 16 = 20[/tex]
The dilution factor of reagent A:
[tex]D.F=\frac{20}{4}=5[/tex]
The dilution of the reagent A = [tex]1:5=\frac{1}{5}[/tex]
1/5 is the dilution of reagent A in water
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